## Chain with N site unit-cell

How do I use this algorithm? What does that parameter do?
xaver
Posts: 5
Joined: 23 Apr 2021, 07:51

### Chain with N site unit-cell

Hello,
this is a stupid newbie's question. Most certainly, the answer I'm looking for is just a pointer to a location in the existing documentation. I'd be grateful for that. I'm trying to implement a model that lives on a chain and has more than a single site per unit cell. So, e.g. for 2 sites per unit cell, something like
$$H=\sum_l t_0 A^+_{0,l}A_{1,l} + t_1 A^+_{1,l}A_{0,l+1} +\mathrm{h.c.}$$
I don't want to 'group' the sites in the unit cell, which probably is not a good idea for local Hilbert space size reasons(?). So, simplistically, I tried to use the init_sites of a CouplingMPOModel, just with a list of sites, i.e., returning [A0Site,A1Site]. But that fails. So (where can I look up) how such a model is implemented properly?
xaver
Posts: 5
Joined: 23 Apr 2021, 07:51

### Re: Chain with N site unit-cell

As usual, I couldn't wait, and tried some more. Let me pls. add to my question and get more specific. For the sake of brevity, let me assume that in my OP I set $$A_{l,j}=S_x$$. Moreover at the risk of crucifixion, let me forget all about charge conservation, boundary conditions and other 'details'. Would then the following be the proper way of setting up the model (if only the H_MPO is needed)

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from tenpy.models.lattice import Lattice
from tenpy.models.model import CouplingModel,MPOModel
from tenpy.networks.site import SpinHalfSite

class dimer(CouplingModel, MPOModel):
def __init__(self, model_params):
#
L = model_params.get('L', 10)
lat = Lattice([L],[SpinHalfSite(conserve=None),SpinHalfSite(conserve=None)])
CouplingModel.__init__(self, lat)
#
t0 = model_params.get('t0', 1.)
t1 = model_params.get('t1', 1.)
self.add_coupling(t0, 0, 'Sx', 1, 'Sx', [0])
self.add_coupling(t1, 1, 'Sx', 0, 'Sx', [1])
#
MPOModel.__init__(self, lat, self.calc_H_MPO())
At least if I do

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c=dimer({'L':4,'t0':1.,'t1':2.})
print(c.all_coupling_terms().to_TermList())
The output looks reassuring

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1.00000 * Sx_0 Sx_1 +
2.00000 * Sx_1 Sx_2 +
1.00000 * Sx_2 Sx_3 +
2.00000 * Sx_3 Sx_4 +
1.00000 * Sx_4 Sx_5 +
2.00000 * Sx_5 Sx_6 +
1.00000 * Sx_6 Sx_7

So is this what one should do - or are there better ways?
Johannes